3v^2-15v+18=0

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Solution for 3v^2-15v+18=0 equation: 



3v^2-15v+18=0

a = 3; b = -15; c = +18;
Δ = b2-4ac
Δ = -152-4·3·18
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3}{2*3}=\frac{12}{6}
=2
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3}{2*3}=\frac{18}{6}
=3
$

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